Group Data By Year, Month, and Day in PostgreSQL

Group by Year, Month, or Day in PostgreSQL

How to group data by specific date interval using DATE_TRUNC(), EXTRACT(), or TO_CHAR() functions in PostgreSQL.

    Introduction

    PostgreSQL is one of the best relational databases that developers use on a daily basis.

    In fact, PostgreSQL supports a wide range of data manipulation and analysis features. One of the most important analysis features is grouping data by a specific interval.

    Let’s represent how PostgreSQL handles this feature elegantly.

    Your Manager Requirements

    Before digging deeper, let’s consider that you have the following orders table:

    idpricecreatedAt
    11002022-01-12 01:15:00
    21202022-02-10 23:44:00
    3802023-01-09 08:14:00
    41502023-07-09 20:50:00
    5502023-07-10 09:33:00
    6302023-07-10 15:23:00
    7902023-09-23 10:12:00

    And your manager asks you three requirements:

    1. Calculate the total sales every year.
    2. Calculate the total sales every month in 2023.
    3. Calculate the total sales every day in July 2023.

    Group by Year

    Let’s solve the first requirement.

    1- Using DATE_TRUNC()

    This function, as its name implies, truncates a date based on a specific date part. You can know more about it here.

    SELECT DATE_TRUNC('YEAR', "createdAt") AS year, SUM("price") AS total
    FROM "orders"
    GROUP BY year
    ORDER BY year

    This statement returns:

    yeartotal
    2022-01-01 00:00:00220
    2023-01-01 00:00:00400

    You might have noticed that the year field returned as a timestamp rounded to a specified level of precision, not as a number.

    To return the year as a number, you can use the following:

    SELECT DATE_PART('YEAR', DATE_TRUNC('YEAR', "createdAt")::TIMESTAMP)::INTEGER AS year
    ...
    ::INTEGER casts the double value returned from DATE_PART() to an integer.

    2- Using EXTRACT()

    This function extracts a year, month, or … from a date. Know more about it here.

    SELECT EXTRACT(YEAR FROM "createdAt")::INTEGER AS year, SUM("price") AS total
    FROM "orders"
    GROUP BY year
    ORDER BY year

    This statement returns:

    yeartotal
    2022220
    2023400

    Unlike the DATE_TRUNC() function, the EXTRACT() function returns the year as a double. So I used ::INTEGER to cast the double value returned from EXTRACT() to an integer.

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    3- Using TO_CHAR()

    This function converts its input to a string. Check it out here.

    SELECT TO_CHAR("createdAt", 'YYYY')::INTEGER AS year, SUM("price") AS total
    FROM "orders"
    GROUP BY year
    ORDER BY year
    ::INTEGER casts the string value returned from TO_CHAR() to an integer.

    This statement returns the same result as EXTRACT().

    Group by Month in a Year

    Let’s solve the second requirement.

    Like grouping by year, you can group by month in a year using the same functions.

    1- Using DATE_TRUNC()

    SELECT DATE_TRUNC('MONTH', "createdAt") AS month, SUM("price") AS total
    FROM "orders"
    WHERE DATE_PART('YEAR', "createdAt") = 2023
    GROUP BY month
    ORDER BY month

    This statement returns:

    monthtotal
    2023-01-01 00:00:0080
    2023-07-01 00:00:00230
    2023-09-01 00:00:0090

    2- Using EXTRACT()

    SELECT EXTRACT(MONTH FROM "createdAt")::INTEGER AS month, SUM("price") AS total
    FROM "orders"
    WHERE DATE_PART('YEAR', "createdAt") = 2023
    GROUP BY month
    ORDER BY month

    This statement returns:

    monthtotal
    180
    7230
    990

    3- Using TO_CHAR()

    SELECT TO_CHAR("createdAt", 'MM')::INTEGER AS month, SUM("price") AS total
    FROM "orders"
    WHERE DATE_PART('YEAR', "createdAt") = 2023
    GROUP BY month
    ORDER BY month

    This statement returns the same result as EXTRACT().

    Group by Day in a Month of a Year

    Let’s solve the third requirement.

    1- Using DATE_TRUNC()

    SELECT DATE_TRUNC('DAY', "createdAt") AS day, SUM("price") AS total
    FROM "orders"
    WHERE DATE_PART('MONTH', "createdAt") = 7 AND DATE_PART('YEAR', "createdAt") = 2023
    GROUP BY day
    ORDER BY day

    This statement returns:

    daytotal
    2023-07-09 00:00:00150
    2023-07-10 00:00:0080

    2- Using EXTRACT()

    SELECT EXTRACT(DAY FROM "createdAt")::INTEGER AS day, SUM("price") AS total
    FROM "orders"
    WHERE DATE_PART('MONTH', "createdAt") = 7 AND DATE_PART('YEAR', "createdAt") = 2023
    GROUP BY day
    ORDER BY day

    This statement returns:

    daytotal
    9150
    1080

    3- Using TO_CHAR()

    SELECT TO_CHAR("createdAt", 'DD')::INTEGER AS day, SUM("price") AS total
    FROM "orders"
    WHERE DATE_PART('MONTH', "createdAt") = 7 AND DATE_PART('YEAR', "createdAt") = 2023
    GROUP BY day
    ORDER BY day

    This statement returns the same result as EXTRACT().

    Conclusion

    In this article, we learned how to group data by a specific date interval, year, month, and day.

    And to do so, we introduced three different ways:

    • DATE_TRUNC()
    • EXTRACT()
    • TO_CHAR()

    Think about it

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    If you’re interested in exploring more, check out these articles.

    Thanks for sticking with me until the end—I hope you found this article valuable and enjoyable!

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